Authorization required for cloning Kallithea with Mercurial >= 6.5.0

[Mads Kiilerich]

Hi Branko

Thanks for reporting.

I have indeed recently caught and pushed support for latest Mercurial 
version and updated the server. But it was apparently not complete.

This should be fixed by 
https://kallithea-scm.org/repos/kallithea-incoming/changeset/0245e0ebddd09c6bcc7b1cd74708cf19a49ee57e 
- can you confirm that?

Regards,
Mads


On 23/07/2024 13:17, Branko Majic wrote:
> Hello,
>
> Attempting to clone the official Kallithea repository (at
> https://kallithea-scm.org/repos/kallithea) anonymously with newer
> versions of Mercurial seems to fail, and prompts user for credentials:
>
> ----%----
> (hgtest) branko at che:~/projects/hgtest$ hg version
> Mercurial Distributed SCM (version 6.5.3)
> (see https://mercurial-scm.org for more information)
>
> Copyright (C) 2005-2023 Olivia Mackall and others
> This is free software; see the source for copying conditions. There is NO
> warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.
>
> Enabled extensions:
>
>    histedit  internal
>    strip     internal
> (hgtest) branko at che:~/projects/hgtest$ hg clone https://kallithea-scm.org/repos/kallithea
> destination directory: kallithea
> http authorization required for https://kallithea-scm.org/repos/kallithea
> realm: Kallithea authentication
> user:
> ----%----
>
> Based on the realm part - I assume this could be something related to
> Kerberos?
>
>  From what I can tell, this happens only with "newer" versions of
> Mercurial - starting with version 6.5.0. I've tested with 6.4.5 and did not get
> prompted for credentials. This testing was all done from within dedicated
> Python virtual environment.
>
> Since I am not experiencing the same issue with my test installation of
> Kallithea, I assume this is related to how the official Kallithea
> instance has been configured. Maybe if it detects that client can do
> Kerberos-based authentication it insists on using it?
>
> Best regards,
> Branko
>
> P.S.
> Of course, could be it's not Kerberos at all, just me jumping to
> conclusions. :)
>
>
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